Question

A roller coaster is moving at 25 m/s at the bottom of a hill. Three seconds later it reaches the top ofthe hill moving at 10 m/s. What was the acceleration of the coaster?​

Answer 1

given,

velocity at starting point : 25m/s

velocity at end : 10m/s

time: 3 seconds

acceleration = v-u/t , where :

u = initial velocity

v = final velocity

t = time

so acceleration of roller coaster

= (10-25)/3 m/s²

= -15/3 m/s²

= -3m/s²

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Answer 2

Answer:

$\huge\color{blue}\boxed{\colorbox{lightgreen}{♧Solution♧}}\bigstar$

intial velocity =2m/s

Final velocity =10m/s

Time taken =3sec

Acceleration (in the case, deceleration)

$= \frac{final \: velocity}{time}$

$= \frac{10 - 25}{3} = \frac{ - 15}{3} =$

-5m/s

Hence This is Answer