Question

A roller coaster is moving at 29 m/s at the bottom of a hill. Three seconds later it reaches the top of the hill moving at 11 m/s. What was the acceleration of the coaster? (2 decimal places!!)

Answer 1

Answer:

v=29ms-¹

u=11ms-¹

t=3s

$a = \frac{v - u}{t} \\ \: \\ a \frac{11 - 29}{3} = - 6{ms}^{ - 2}$

Explanation:

see your initial velocity was 29m/s or ms-¹ which is denoted as u

next is your final velocity which was 11m/s or ms-¹ which is denoted as v

next is time which is 3s

next is acceleration's formual which is a=v-u/t now simply putting values in we get -6m/s²