A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4.0 m/s2. What is the final velocity of the roller coaster?
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Given:
- Initial velocity, u = 13m/s
- Distance, s = 400m
- Acceleration, a = 4m/s²
To find:
- Final velocity, v
Solution:
★ Using 3rd eqⁿ of motion,
- v² = u² + 2as
⇒ v² = 13 × 13 + 2 × 4 × 400
⇒ v² = 169 + 3200
⇒ v² = 3369
⇒ v = √3369
⇒ v = 58m/s
- Hence, the final velocity of the roller coaster is 58m/s.
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