Question

A roller coaster velocity at the top of a hill is 10 m/s. Two seconds later it reaches the bottom of the hill with a velocity of 26 m/s. What was the acceleration of the coaster

Answer 1

Answer:

the answer is 8 meter per second*2

Explanation:

by using the newtons first law of motion

data:

Vf = 26 meter per second

Vi = 10 meter per second

and time t = 2 seconds

and we have to find acceleration a =?

Vf = Vi + a t

after re-arranging we get

a = ( Vf - Vi ) / t

by putting their values we get answer 8 meter per second*2

regards

M Faizan

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thank u ...

Answer 2

Aɴꜱᴡᴇʀ

☞ Acceleration of the roller coaster is 8 m/s²

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Gɪᴠᴇɴ

➳ Initial velocity (u) = 10 m/s

➳ Final velocity (v) = 26 m/s

➳ Time (t) = 2 seconds

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Tᴏ ꜰɪɴᴅ

➤ The acceleration of the body?

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Sᴛᴇᴘꜱ

✭ The answer to the question can be found with the help of the first equation of motion, that is,

$\large{ \underline{ \boxed {\sf{ v = u + at}}}}$

Substituting the given values,

$\large \tt \leadsto{}26 = 10 + a \times 2 \\ \\ \large \tt \leadsto26 - 10 = 2a \\ \\ \large \tt \leadsto16 = 2a \\ \\ \large \tt \leadsto \frac{16}{2} = a \\ \\ \large{ \pink{ \leadsto{ \tt{}a = 8 \: m/ {s}^{2} }}}$

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