Question

A roller coasters accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. What's the acceleration?

Answer 1

Step-by-step explanation:

Given:

• Initial velocity (u) = 6 m/s
• Initial velocity (u) = 6 m/sFinal velocity (v) = 70 m/s
• Initial velocity (u) = 6 m/sFinal velocity (v) = 70 m/sTime (t) = 4 seconds

To find:

• Acceleration (a) = ?

Solution:

♧ Acceleration (a) = Final velocity (v) - Initial velocity (u) ÷ Time (t) ♧

(putting values)...

--> a = 70 - 6 ÷ 4

--> a = 64 ÷ 4

--> a = 16 m/s^2

Hence, the acceleration = 16 m/s^2

Hope it helped you dear...

Answer 2

Given Here

Initial velocity (u) = $6m/s$,

Final velocity (v) = $70 m/s$,

Time = $4 sec$

Find out here Acceleration (a) = ?,

For calculation of acceleration, we put the formula of acceleration,

Acceleration (a)= Final velocity(v)-inital veloctiy(u) ÷ time,

i.e

$a=\frac{v-u}{t}$,

Now substituting the value in the above equation,

$a=\frac{70-6}{4} ,\\a=\frac{64}{4} ,\\a=16 m/s$

Therefore the acceleration of roller coasters will be $16 m/s$