Question

A roller is pushed with a force of 100 N along its handle which is at an angle 30 degree with the horizontal find the work done in moving it through 10 m

Answer 1

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ

ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ

ⓐⓝⓢⓦⓔⓡ



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$workdone = fs \cos(30)$



$workdone = 100 \times 10 \times \frac{ \sqrt{3} }{2}$



$workdone = 500 \sqrt{3} joules$





Hope it helps you



$<marquee > prabhudutt$

Answer 2

Force= 100 N
displacement,s= 10 m
So, Work done ,W= F.s
W = Fs cos30
W= 100×10× √3/2
W = 173× 5 = 865 J