A roller of height 10 m and radius 0.35 m is used to level a lawn. Find the area (in sq. m) it can level in one full rotation.
Answers
Answered by
1
Answer:
2*22/7*0.35*10
calculate it to get the answer
Answered by
0
Answer:
Diameter = 1.4 m
r = d/2
r = 1.4/2
r = 0.7 m
curved surface area of cylinder =2
∗
22/7
∗
r∧2
=2
∗
22/7
∗
0.7
∗
0.7
=8.8m
∧
2
No of revolution = 5
Therefore =8.8
∗
5
= 44 m2
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