Question

A roller of height 10 m and radius 0.35 m is used to level a lawn. Find the area (in sq. m) it can level in one full rotation.​

Answer 1

Answer:

2*22/7*0.35*10

calculate it to get the answer

Answer 2

Answer:

Diameter = 1.4 m

r = d/2

r = 1.4/2

r = 0.7 m

curved surface area of cylinder =2

∗

22/7

∗

r∧2

=2

∗

22/7

∗

0.7

∗

0.7

=8.8m

∧

2

No of revolution = 5

Therefore =8.8

∗

5

= 44 m2

Please mark as brainliest