Question

A roller of mass 300kg and of radius 50cm lying on horizontal floor is resting against a step of height 20cm. The minimum horizontal force to be applied on the roller passing through its centre to turn the roller on to the step is :

Answer 1

Balancing torque about the highest point of the step ( corner point )

F min ×30=40mg

⇒F min = 40×300×9.8/30

=3920N.

Answer 2

Answer:

3920

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Explanation: