Physics, asked by vkereeeti8850, 10 months ago

A roller of mass 300kg and of radius 50cm lying on horizontal floor is resting against a step of height 20cm. The minimum horizontal force to be applied on the roller passing through its centre to turn the roller on to the step is :

Answers

Answered by Anonymous
2

Balancing torque about the highest point of the step ( corner point )

F min ×30=40mg

⇒F min = 40×300×9.8/30

=3920N.

Answered by vamshivardhan22
0

Answer:

3920

make me brain list

Explanation:

Similar questions