A roller of mass 300kg and of radius 50cm lying on horizontal floor is resting against a step of height 20cm. The minimum horizontal force to be applied on the roller passing through its centre to turn the roller on to the step is :
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Balancing torque about the highest point of the step ( corner point )
F min ×30=40mg
⇒F min = 40×300×9.8/30
=3920N.
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Answer:
3920
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