Question

A room 11m 47cm long and 7m 77cm broad is to be paved with square tiles. Find the least number of tiles required to cover the floor

Answer 1

Minimum 28 tiles required

Answer 2

Answer:

The number of tiles required to cover the floor is 651.

Step-by-step explanation:

Given : A room 11m 47cm long and 7m 77cm broad is to be paved with square tiles.

To find : The least number of tiles required to cover the floor?

Solution :

The length of the room is  11m 47cm.

$11\text{ m } 47\text{ cm }=1100 \text{ cm }+47\text{ cm }=1147 \text{ cm }$

The breadth of the room is 7m 77cm.

$7\text{ m } 77\text{ cm }=700 \text{ cm }+77\text{ cm }=777 \text{ cm }$

Now, We find the HCF of 1147 and 777 is

$1147=31\times 37$

$777=3\times 7\times 37$

The HCF of 1147 and 777 is 37.

The area of the each tile with side 37 cm is

$A=37\times 37=1369 cm^2$

So, The required number of tiles is given by,

$n=\frac{1147\times 777}{1369}$

$n=\frac{891219}{1369}$

$n=651$

Therefore, The number of tiles required to cover the floor is 651.