Math, asked by nidumolphani, 4 months ago

A room, 15 m long, 4 m high and 5 m wide has three doors 3 m by 2.5 m and three windows 2 m by 0.75 m. If the cost of colouring the walls and the ceiling is ` 20 per sq. m, then find the total cost of polishing the walls and
ceiling.........pls answer

Answers

Answered by devindersaroha43
4

Answer:

Step-by-step explanation:

Answer

4.0/5

66

student65

area of room=2×h(l+b)

=2×4.2 (10+6)

=8.4×16

=134.4sq.m

area of door =2.5×1.5

=3.75sq.m

area of Window =1.5×1

=1.5sq.m

area of walls=room-door-window

=134.4 -3.75 -1.5

=132.15sq.m

cost of whitewashing =132.15×2.50

=333.075rupees

Answered by SakshamKumarthegreat
1

Answer:

The roof will have the same dimensions as the floor which are the length and breadth as given in the question.

The roof will have the same dimensions as the floor which are the length and breadth as given in the question. Hence, area

of \: the \: roof \:  =  \: 5 \:   \times  \: 4.5 \:  =  \: 22.5 {}^{2}

Cost of painting the roof at the rate of Rs 9 per

m {}^{2} \:  =  \: 9 \times 22.5 =  Rs 202.5</strong></h3><h3></h3><h3><strong>[tex]m {}^{2} \:  =  \: 9 \times 22.5 =  Rs 202.5

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