Math, asked by Anonymous, 5 months ago

A room 5 m by 4 m by 3 m has a marble flooring. Its walls and ceilings have been
painted light blue. Find the cost of marbling the floor at the rate of * 200 per sq m and
painting the walls and ceilings at the rate of 50 per sq m.​

Answers

Answered by Anonymous
2

Answer:

total cost of marbling and = rs 7700

Step-by-step explanation:

solution -

l= 5 m , b = 4 m , h= 3m

area of the floor = 5×4 = 20m^2

surface area of six faces

= ( lb +bh +hl )

= 2 ( 5×4 +4× 3 +3× 5) m^2

= 2 ( 20 + 12 + 15 )m^2

= 2×47m^2 = 94 m^2

area of the walls and ceilings = 94 m^2 - area of the floor

= 94 m^2 -20m^2= 74m^2

cost of marbling 1 m^2= rs 200

cost of 20 m^2 = 200×20 = rs 4000

cost of painting 1m^2 = rs 50

cost of painting 74 m^2 = 50×74 =rs 3700

total cost of marbling and painting = rs 4000 + 3700= rs 7700

Answered by Anonymous
1

Answer:

total cost of marbling and = rs 7700

Step-by-step explanation:

solution -

l= 5 m , b = 4 m , h= 3m

area of the floor = 5×4 = 20m^2

surface area of six faces

= ( lb +bh +hl )

= 2 ( 5×4 +4× 3 +3× 5) m^2

= 2 ( 20 + 12 + 15 )m^2

= 2×47m^2 = 94 m^2

area of the walls and ceilings = 94 m^2 - area of the floor

= 94 m^2 -20m^2= 74m^2

cost of marbling 1 m^2= rs 200

cost of 20 m^2 = 200×20 = rs 4000

cost of painting 1m^2 = rs 50

cost of painting 74 m^2 = 50×74 =rs 3700

total cost of marbling and painting = rs 4000 + 3700= rs 7700

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