Math, asked by sukrititom7537, 1 year ago

A room 5m long,4.5m wide and 3.6m high has one door 1.5m by 2.4 and two windows each 1m by 0.75m find The area of its walls, excluding doors and windows The cost of distempering it's walls at the rate of â¹4.50 per m^2 The cost of painting it's roof at the rate of â¹9 per m^2

Answers

Answered by oshika
2
total area of the four walls = (2*3.6*5)+(2*3.6*4.5)
                                          = (36 + 32.4) = 68.4 m^2
area of the door = 1.5*2.4 = 3.6 m^2
area of the two windows = 2*1*0.75 = 1.5 m^2
area of the wall excluding door and windows = (68.4 - 5.1) m^2
                                                                        = 63.3 m^2
cost of distempring its walls = 4.5*63.3 = rupees 274.85
cost of painting its roof = 9*5*4.5 = 202.5 rupees
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