Question

A room 6m long and 4.5m wide needs 1000 tiles for its floor. How many tiles will be needed for a hall 12m long and 9m wide.

Answer 1

length of the room (L)=6m
width of the room (W)=4.5m
so, Area for first room is (A)=L×W
=(6×4.5)
=27m^2
no. of tiles for first room (N)=1000
and by N=
$\frac{area \: of \: room }{area \: of \: tile}$
so, 1000 = 27/area of tile
area of tile is (a) =27/1000 m^2.
now,
for hall of length (l)=12m
and width (w)=9m
so, the area of hall =108m^2
we require no. of tiles so again by above formula N=
$\frac{area \: of \: hall}{area \: of \: tile}$
N = (108/27)×1000
hence the answer is 4000.

Answer 2

area of the room(1st) = 6m×4.5m=600cm×450cm=270000cm²

⇒area of each tile=270000÷1000 =270cm²

area of 2nd room= 12m ×9m=1200cm ×900cm =1080000cm²

⇒number of tiles needed for the second room= area of room÷area of each tile

=1080000cm²÷270cm²=4000

ans) 4000 tiles are needed