A room 6m long and 4.5m wide needs 1000 tiles for its floor. How many tiles will be needed for a hall 12m long and 9m wide.
Answers
Answered by
2
length of the room (L)=6m
width of the room (W)=4.5m
so, Area for first room is (A)=L×W
=(6×4.5)
=27m^2
no. of tiles for first room (N)=1000
and by N=
so, 1000 = 27/area of tile
area of tile is (a) =27/1000 m^2.
now,
for hall of length (l)=12m
and width (w)=9m
so, the area of hall =108m^2
we require no. of tiles so again by above formula N=
N = (108/27)×1000
hence the answer is 4000.
width of the room (W)=4.5m
so, Area for first room is (A)=L×W
=(6×4.5)
=27m^2
no. of tiles for first room (N)=1000
and by N=
so, 1000 = 27/area of tile
area of tile is (a) =27/1000 m^2.
now,
for hall of length (l)=12m
and width (w)=9m
so, the area of hall =108m^2
we require no. of tiles so again by above formula N=
N = (108/27)×1000
hence the answer is 4000.
Answered by
1
area of the room(1st) = 6m×4.5m=600cm×450cm=270000cm²
⇒area of each tile=270000÷1000 =270cm²
area of 2nd room= 12m ×9m=1200cm ×900cm =1080000cm²
⇒number of tiles needed for the second room= area of room÷area of each tile
=1080000cm²÷270cm²=4000
ans) 4000 tiles are needed
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