Question

A room 6m long and 4m wide needed 1000Tile for it's floor .How many tiles will needed to cover a hall of 12m long and 8m wide​

Answer 1

Answer:

4000 tiles

Step-by-step explanation:

Length 1=6m

Bredth 1 =4m

Area 1 =6X4 = 24m

Tiles1 = 1000

Length 2=12m

Bredth 2 =8m

Area 2 =12X8 = 96m

Tiles2 = x

if we solve this question by unitary method the equation for this will be

tiles1/area1=tiles2/area2

that equals to 1000/24=96x

= 1000*96/24=x

= 96000/24=x

= 4000/1=x(24 * 4 = 96, 24 * 4000 = 96000)

= x = 4000

hope this will help you