Math, asked by expertguru2664, 1 year ago

A room 8 m long 5 m broad and 4 m high has two door 1.5 m by 1 m and three window each 1.2 m by 80cm find area of four walls excluding doors and window

Answers

Answered by ShaikJavidbasha
0

Answer:

Step-by-step explanation:

length ,breadth and height of the room are 8m ,5m ,and 4m

area of room = lxbxh

8x5x4 = 160 m therefore area of room is 160m

length and breadth of two doors is 1.5 and 1m

area of two door = 2x1.5x1 =3

length ane breadth of window is 1.2m and 80cm

80cm = 0.8m

area of 3 windows = 3x1.2x08 = 2.88m

area of walls =total area of room - area of windows and doors

area of walls = 160-5.88 = 154.12m

Therefore area of walls excluding doors and windows is 154.12m

Answered by amitnrw
3

Answer:

A room 8 m long 5 m broad and 4 m high has two door 1.5 m by 1 m and three window each 1.2 m by 80cm Then area of four walls excluding doors and window = 98.12 m²

Step-by-step explanation:

Area of 4 walls =  2 * (8 * 4  + 5*4) = 104 m²

Area of two doors = 2 * 1.5 * 1 = 3 m²

Area of Three windows = 3 * 1.2 * (80/100) = 2.88 m²

area of four walls excluding doors and window = 104 - 3 - 2.88 = 98.12 m²

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