A room 8 m long 5 m broad and 4 m high has two door 1.5 m by 1 m and three window each 1.2 m by 80cm find area of four walls excluding doors and window
Answers
Answer:
Step-by-step explanation:
length ,breadth and height of the room are 8m ,5m ,and 4m
area of room = lxbxh
8x5x4 = 160 m therefore area of room is 160m
length and breadth of two doors is 1.5 and 1m
area of two door = 2x1.5x1 =3
length ane breadth of window is 1.2m and 80cm
80cm = 0.8m
area of 3 windows = 3x1.2x08 = 2.88m
area of walls =total area of room - area of windows and doors
area of walls = 160-5.88 = 154.12m
Therefore area of walls excluding doors and windows is 154.12m
Answer:
A room 8 m long 5 m broad and 4 m high has two door 1.5 m by 1 m and three window each 1.2 m by 80cm Then area of four walls excluding doors and window = 98.12 m²
Step-by-step explanation:
Area of 4 walls = 2 * (8 * 4 + 5*4) = 104 m²
Area of two doors = 2 * 1.5 * 1 = 3 m²
Area of Three windows = 3 * 1.2 * (80/100) = 2.88 m²
area of four walls excluding doors and window = 104 - 3 - 2.88 = 98.12 m²