Question

a room 8 metre long and 6 metre wide its floor to be covered with rectangular tile of size 25 metre by 20, find the cost of tiles required at the the rate rupees 20 per tile​

Answer 1

Answer:

Answer

Correct option is

D

Rs. 14875

Area of room → Length X Breadth

Area of room → 1150 ×630 → 724500 sq. cm

Area of 1 tile → 23×9 → 207 sq. cm

Number of tiles required →

Area of tile

Area of room

Number of tiles required →

207

724500

→ 3500

Cost of tiling → (Number of tiles) × (Cost of 1 tile) → 3500×4.25 → 14875

Step-by-step explanation:

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Answer 2

Answer:

19200 rs

Step-by-step explanation:

Given:-

• Length of the room = 8 mtr
• Breadth of the room = 6 mtr
• Length of rectanguler time wchich is about to use for cover room = 25 cm
• Breadth of the rectanguler tile '' '' '' = 20 cm
• Cost of one tile = 20 rs

To Find:-

Cost of tile which ia about to use for covering the floor

Solution:-

• Area of floor = Length x Breadth

8 x 6 = 48 sq m

change 48 sq m in to sq cm

48 x 100 x 100 = 480000 sq cm

• Area of the tile = Length x breadth

25 x 20 = 500 sq cm

Total tiles required for cover the floor = 480000/500 = 960 tiles

• Cost of one tile = 20 rs

Thus cost of 960 tile = 960 x 20 = 19200 rs