Question

-A room 9.5 m long and 6 m wide is surrounded by a 1.25-m-wide verandah. Calculate the
cost of cementing the floor of this verandah at 80 rupees per m².
pls help​

Answer 1

Answer:

1.65 is the right answer

Step-by-step explanation:

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Answer 2

Given :-

Length of the room = 9.5 m

Breadth of the room = 6 m

Cost of cementing the floor per meter square = Rs. 80

To Find :-

Area of the room.

Cost of cementing the floor of this verandah.

Analysis :-

Find the area of the room using the formula of area : Length × Breadth

Get the length ad breadth of the verandah accordingly and find it's area.

Next find the area of the verandah by subtracting the area of the room from the area including the verandah.

Multiply the area you got to the cost of cementing per square meter.

Solution :-

We know that,

• l = Length
• b = Breadth
• a = Area

Given that,

Length (l) = 9.5 m

Breadth (b) = 6 m

Area of a rectangle is given by,

$\underline{\boxed{\sf Area \ of \ a \ rectangle=Length \times Breadth}}$

Substituting their values, we get

Area of the room = $\sf 6 \times 9.5=57 \ m$

Finding the length of the verandah,

The length of verandah = Length of the room + Width of the verandah × 2

Substituting them,

$\implies \sf 9.5 + 1.25 \times 2 = 12 \ m$

Next finding the breadth of the verandah,

Breadth of the verandah = Width of the room + Width of the verandah × 2

Substituting them,

$\sf \implies 6+1.25 \times 2 = 8.5 \ m$

Finding the area of the verandah,

Area of a rectangle = Length × Breadth

Substituting their values,

The area of verandah = $\sf 12 \times 8.5 = 102 \ m^{2}$

∴ Total area of room = $\sf 102 - 57 = 45 \ m^{2}$

Given that, cost of cementing per meter square = Rs. 80

Now, finding the cost of cementing,

Cost of cementing the floor = Cost per square meter × Total area of the room

Substituting their values,

Cost of cementing = $\sf 80 \times 45$

Cost of cementing = 3600

Therefore, cost of cementing is Rs. 3600