a room has dimensions 9m×8m×6.5m . it has one door of dimensions2m×1.5m and 3 windows each of dimensions 1.5m×1 m find the cost of of the whitewashing the walls of rs 3.80 per m^2
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Answer :
Cost of whitewashing the walls = Rs. 1358.50
Solution :
Area of the room
= 2 {(9 × 8) + (8 × 6.5) + (6.5 × 9)} m²
= 2 (72 + 52 + 58.5) m²
= 2 × 182.5 m²
= 365 m²
Area of the door
= 2 × 1.5 m²
= 3 m²
Area of the 3 windows
= 3 × 1.5 × 1 m²
= 4.5 m²
∴ the area of the walls
= (Area of the room) - (Area of the door + Area of the 3 windows)
= 365 - (3 + 4.5) m²
= 365 - 7.5 m²
= 357.5 m²
Hence, the cost of whitewashing the walls
= cost of whitewashing per m² × the area of the walls
= Rs. 3.80 × 357.5
= Rs. 1358.50
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