a room has the dimensions of 8m into 6m into 4m find the cost of part required to paint the walls of the room if the cost of paint is rupee 80 per sq.cm
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Answer:
Given:
length=8m
breath=6m
height=4m
to find:
the cost of painting if 80rs per cm²
proof:
TSA of a cuboid=2(lb+bh+hl)-(lb)units (coz no one will paint for floor)
2[(8×6)+(6×4)+(4×8)]-(8×6)m
2(48+24+32)-48 m
2(104)-48m
208-48=160m²
therefore the tsa of the room is 160m²
160m²=16000cm²
the cost of painting the room is 80×16000
RS =12,80,000
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