Question

A room has two rectangular walls of dimensions 20 × 16 feet and two square walls of dimensions
16 × 16 feet. One of the square walls has a door of dimensions 8 × 3 feet. Find the cost of
painting the room at the rate of Rs 0.5 per square feet :
EXPLAIN THEN I WILL MARK YOU AS BRAINLIEST

Answer 1

Answer:

It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m2

Area of the ceiling is: 

A=l×b=8×5=40 m2

Total area of the four walls and the ceiling of the room is 78+40=118 m2

It is given that cost of white washing is Rs.15/m2, therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770.

Answer 2

Answer:

area of rectangle = length* breadth

so that = (20*16)2 = 640

area of square = a^2

sq= (16^2)2= 512

area of door length *breadth

8*3=24 which substract from one wall therefore

512-24=488

and total area which is to be paint = 640 + 488 =

1128 and cost of painting = 0.5*1128=

₹564

I hope u will understand calculation check kar liyo bhai.. formula thik hai