Question

A room is 10.2 m long, 8.5 m wide and
4.6 m high. It has a door measuring
1.5 mx 2.6 m and a window measuring
2 mx 1.7 m. Find the cost of tiling the​

Answer 1

Answer:

Area of the 4 walls = 2(l+b)×h sq. units

= 2(10.2+8.5)×4.6 m sq.

= 2×18.7×4.6 m sq.

= 172.04 m sq.

Area of a door = l×b sq. units

= 1.5×2.6 m sq.

= 3.9 m sq.

Area of a window = 3.4 m sq. [ l×b ]

Total tilling area = Area of 4 walls- (area of a

door + area of a window)

= 172.04 - (3.9 + 3.4) m sq.

= 164.74 m sq.

Total cost = Rs. (13.50×164.74)

= Rs. 2223.99

= Rs. 2224

Step-by-step explanation:

Answer 2

first we have to find CSA(curve surface area) of room

so,2(l+b)*h

=2(10.2+8.5)*4.6=172.04 sq. m.

Now,we have to find area of window and door

so, area of window + area of door

=2*1.7+1.5*2.6=7.3 sq. m.

now, subtract

172.04-7.3=164.74 sq.m

so rate=164.74*13.50=2223.99 RS.

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