Question

A room is 10 meter long and 8 m wide .lt's floor is paved with square tiles of side 50 cm . How many tiles will be required ?

Answer 1

Hey Mate
Length=10m
= 1m=100cm
=10×100
=1000cm
Breadth=8m
=1m=100cm
=8×100
=800cm
Area= 800×1000
$l \times b$
$800 \times 1000 = 800000$

Side of one side of the square tile = 50 cm
Area of one square tile =
$s \times s$
$50 \times 50 = 2500$
No. of tiles required =
$\frac{total \: area \: of \: the \:room }{area \: of \: one \: tile}$

$\frac{800000}{2500} = 320tiles$
Hope it helps you!!!
Please as brainliast

Answer 2

$\textbf{\large{\underline{\underline{ANSWER::}}}}$

As given ;

A room is 10 meters long and 8 meters wide. We have to find number of square tiles of 50 cm side each used to pave the whole floor.

The measurements of square tile and room is different so, first we have make them alike.

As we know that;
1 m = 100 cm

So,
➡10 m = 100 cm × 10
= 1000 cm.
➡8 m = 100 cm × 8
= 800 cm

$\textbf{Area of room =}$ 1000 cm × 800 cm.
= 800000 ${cm}^{2}$

Now, we have to find area of square tiles.

$\textbf{Area of square tiles =}$ 50 cm × 50 cm
= 2500 ${cm}^{2}$

$\textbf{Number of tiles=}$
$\dfrac{Area \:\:of\:\: room}{Area\:\: of\:\: tiles}$

= $\dfrac{800000\: {cm}^{2}}{2500\: {cm}^{2}}$

= 320.

Therefore, $\textbf{\underline{320 tiles}}$are needed to be paved on the floor