A room is 10m long, 6m broad and 5m High it has one door of dimensions 2 m by 1.5 m and 2 Windows each of dimensions 1m by 1m .Find the cost of whitewashing the walls at rupees 20 per square metre
Answers
Answer:
Step-by-step explanation:
area of room = lxbxh
=10x6x5 =300m
area of door = lxbxh
=2x2x1.5=6m
whitewashing the walls = area of room - area of door
= 300cm -6 cm
=294 m
whitewashing 1 m= rs. 20
whitewashing 294m =294x 20
= rs. 5880
Step-by-step explanation:
Area of room = 2 ( l + b ) × h
= 2 ( 10 + 6 ) × 5
= 160 squ. m.
Now, Area of door = l × b
= 2 × 1.5
= 3 squ. m
Area of window = Side × side
= 1 × 1
= 1 squ. m
There are 2 windows so total area of windows will be 2 squ. m.
Now, Area of walls = Area of room - ( Area of door + area of windows )
= 160 - ( 3 + 2 )
= 155 squ.m.
Cost of whiteashing the walls = 155 × 20
= 3100 rs.