Question

A room is 12 m by
by 10 m. find the coast of covering its floor with bricks 20 cm by 6 cm, if the coast
of one thousand bricks is rs 220​

Answer 1

Answer:

Coast of covering the floor with bricks = ₹2200

Step-by-step explanation:

Area of the Room = l × b = 12 × 10 = 120m²

Area of one brick = 20cm × 6 cm or 0.2 m × 0.06 m

= 0.012m²

Number of bricks, that can be laid in 120m² = 120/0.012

= 120000/12 = 10,000

The cost of 1000 bricks is ₹220

So the cost of 10,000 bricks = 10 × 220

= ₹2200

Answer 2

$\bigstar \mid$ GIVEN :

• The room is of 12m by 10m.
• The area of the brick by which it will be covered is 20cm by 6cm.
• The cost of 1,000 bricks is ₹200.

$\bigstar \mid$ TO FIND :

• The cost of covering the floor if rate is ₹200 per 1000 bricks.

$\bigstar \mid$ SOLUTION :

We know that,

The floor is rectangular

${\bf \therefore \: Area \: of \: the \: rectangular \: floor =}{ l \times b}$

$\sf \to \: (12 \times 10) {m}^{2}$

$\sf \to \: 120 {m}^{2}$

NOW,

we are also known that brick is a rectangular in shape

${ \bf \therefore \: Area \: of \: the \: rectangular \: brick = }{l \times b}$

$\sf \to \: (20 \times 6) {cm}^{2}$

$\sf \to \: 120 {cm}^{2} \: or, \: 0.0120 m^2$

THEREAFTER,

$\bf \therefore \: total \: bricks \: needed \: = \frac{area\: of \:the \: floor }{area \: of \: the \: brick}$

$\sf \: \to \: \frac{120 {m}^{2} }{0.0120 {m}^{2} }$

$\sf \to \: \frac{ \cancel{120} \times 10000}{ \cancel{120}}$

$\to {\underline{ \boxed{\bf \: 10000 \: bricks}}}$

HENCE,

$\sf \therefore \: if \: cost \: of \: 1000 \: bricks \:is \to 220$

$\sf \therefore \: then \: cost \: of \: 1 \: brick \: will \: be \to \frac{220}{1000}$

$\sf \therefore \: cost \: of \: 1000 \: will \: be \to \: \frac{220}{ \cancel{1000}} \times \cancel{ 1000}$

$\bf \to \:{ \underline{ \boxed{ \bf ₹220 \: }}}$

FINALLY,

$\bf \: Total \: spenditure \: of \: bricks \: is\: : \\ \bf \red \dag {\underline{\boxed{\bf {\orange {₹220 ☞ ans. \: \: \: \: \: \: \:}}}}}{\red\dag}$