A room is 13m long, 9m broad and 10m high. Find the cost of preparing the four walls of the room at Rs.10/- per Sq. m. It is being given that doors and windows occupy 40 Sq.m.
Answers
Answer: 4000 rs
Step-by-step
Lateral Surface area = 2 height(length + breadth)
= 2 * 10 ( 13+9)
= 20 * 22
= 440 sqr m
after excluding windows and doors = 440- 40
= 400 sqr m
cost = 400*10
= 4000 rs
Answer:
Rs4000
Step-by-step explanation:
Given:
Length of room = 13m
Breadth of room = 9m
Height of room = 10m
Cost= Rs10/sq metre
Doors and windows= 40sq.m
To find: Total sot of preparing the the 4 walls of the room
To solve this, we shall use an equation:
Lateral Surface area= 2Height (Length+Breadth)
Area= 2H (L+B)
i.e.,
- Area= 2 (10) (13+9)
- Area= 20 (22)
- Area= 440 sq.m
Area of the doors and windows= 40Sq.m
Wall area= Total area - are of walls and doors
= 440- 40
=400 sq.m
Total cost= Total area x cost
Total cost= 400 x 10
Total cost= Rs4000
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