Question

A room is 14 m long, 9.5 m broad and 4 m high. It has one door 2 m by 1.5 m and three
windows each of dimensions 1.4 m by 75 cm. Find the cost of distempering the walls of the
room from inside at the rate of 18 per m^2
pls answer fast ​

Answer 1

Answer:

L= 14 m

B=9.5

H=4

2(l+b)

2(14+9.5)4

28(10.9)4

30.52

30.52-4

30.48×28 =953.44 per m sq

Answer 2

cost of distempering the walls is Rs.  3273.3

Step-by-step explanation:

length of the room = 14 m

breadth of the room =  9.5 m

height of the room = 4 m

area of four walls = 2(l+b)h

= 2(14+9.5) × 4

= 8 ×23.5

= 188 m²

length of the door = 2 m

breadth of the door = 1.5 m

area of the one door = l×b

= 2×1.5

= 3 m²

length of the window = 1.4 m

breadth of the window = 75 cm = 0.75 m

area of the three windows = 3(l×b)

= 3(1.4 × 0.75)

= 3×1.05

= 3. 15 m²

area of the wall to be distempered = area of four walls - (area of one door + area of the three windows)

area of the wall to be distempered = 188 -(3+3.15)

= 188 - 6.15

= 181.85 m²

cost of distempering  1 m² = Rs. 18

cost of distempering  181.85 m² = 181.85 × 18 = Rs. 3273.3

hence ,

cost of distempering the walls is Rs.  3273.3

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