A room is 14m long, 9.5m broad and 4m high. It has 3 windows
each of dimension 1.4m by 0.75m, Find the cost of white washing the
walls of the room at the rate of Rs 18 per m².
Answers
cost of distempering the walls is Rs. 3273.3
Step-by-step explanation:
length of the room = 14 m
breadth of the room = 9.5 m
height of the room = 4 m
area of four walls = 2(l+b)h
= 2(14+9.5) × 4
= 8 ×23.5
= 188 m²
length of the door = 2 m
breadth of the door = 1.5 m
area of the one door = l×b
= 2×1.5
= 3 m²
length of the window = 1.4 m
breadth of the window = 75 cm = 0.75 m
area of the three windows = 3(l×b)
= 3(1.4 × 0.75)
= 3×1.05
= 3. 15 m²
area of the wall to be distempered = area of four walls - (area of one door + area of the three windows)
area of the wall to be distempered = 188 -(3+3.15)
= 188 - 6.15
= 181.85 m²
cost of distempering 1 m² = Rs. 18
MARK BRAINLIEST
LIKE
RATE
FOLLOW
cost of distempering 181.85 m² = 181.85 × 18 = Rs. 3273.3
hence ,
cost of distempering the walls is Rs. 3273.3
Answer:
- Cost of whitewashing the walls of the room is ₹3327.3
Step-by-step explanation:
Given that:
- Length of the room = 14 m
- Breadth of the room = 9.5 m
- Height of the room = 4 m
- There are three windows in the room.
- Dimension of each window is 1.4 m by 0.75 m.
- Cost of whitewashing is ₹ 18/m².
To find:
- Cost of whitewashing the walls of the room.
Formulas Used:
Area of 4 walls of a room:
Area of rectangle:
= (L × B)
Where,
- L = Length
- B = Breadth
- H = Height
Solution:
Area of walls of the room:
Adding 14 and 9.5,
Opening the brackets,
Multiplying 47 and 4,
Hence, area of the walls of the room is 188 m².
Area of 1 window = (1.4 × 0.75)
= 1.05
∵ Area of 1 window is 1.05 m².
∴ Area of 3 windows = (1.05 × 3)
= 3.15 m²
Actual area of the walls of the rooms:
= (188 - 3.15) m²
= 184.85
Cost of whitewashing the walls at ₹ 18/m²:
= ₹(184.85 × 18)
= ₹ 3327.3
Hence, cost of whitewashing the walls of the room is ₹3327.3