Question

A room is 14m long, 9.5m broad and 4m high. It has one door 2m by 1.5m and three windows each of dimensions 1.4m by 75cm . Find the cost of distempering the walls of the room from inside at the rate of 80 paise per m²​

Answer 1

Answer:

Length of the room = 5 m

Breadth of the room = 4.5 m

Height of the room = 3.6 m

Area of the roof = L × B

= 5 × 4.5 m2

= 22.5 m2

Area of four walls = 2[L + B] × H

= 2[5 + 4.5] × 3.6

= 2(9.5) × 3.6

= 19 × 3.6

= 68.4 m2

Area of one door = 1.5 × 2.4 m2

= 3.60 m2

= 3.6 m2

= 68.4 m2

Area of one window = 1 × 0.75 m2

= 0.75 m2

Area of 2 windows = 0.75 × 2 m2

= 1.5 m2

(i) Area of four walls excluding door and windows

= 68.4 – (3.6 + 1.5)

= 68.4 – 5.1

= 63.3 m2

(ii) Cost of distempering four walls @ Rs. 4.50 per m2

= 63.3 × 4.50

= Rs. 284.85

(iii) Cost of painting the roof @ Rs. 9 per m2

= 22.5 × 9

= Rs. 202 .50