Math, asked by Chirashreepurkait, 5 months ago

A room is 15 m long and 8m wide . It's floor is to be covered with rectangular tiles each measuring 20cm by 8cm . Find how many tiles will be required .​

Answers

Answered by Anonymous
3

Answer:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and

Step-by-step explanation:

16 tiles required

Answered by varshakumari452
1

Answer:

We know, 50cm=0.5m and

25cm=0.25m

Tiles along the length of the room=

0.5

15

= 30 tiles

Tiles along the length of the room=

0.25

8

=32 tiles

Total number of tiles required =30×32 =960 tiles

To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.

Therefore,

(15−2)m(8−2)m

=(13×6)m

=78m

2

Therefore, the room area is 15×8 = 120m

2

The carpet area is 78m

2

The fraction of the area uncovered =

120

120−78

=

120

42

=

20

7

Step-by-step explanation:

hope it helps you

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