A room is 15 m long and 8m wide . It's floor is to be covered with rectangular tiles each measuring 20cm by 8cm . Find how many tiles will be required .
Answers
Answer:
ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
You should then multiply (−8x−3) and (ax−2) using FOIL.
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and
Step-by-step explanation:
16 tiles required
Answer:
We know, 50cm=0.5m and
25cm=0.25m
Tiles along the length of the room=
0.5
15
= 30 tiles
Tiles along the length of the room=
0.25
8
=32 tiles
Total number of tiles required =30×32 =960 tiles
To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.
Therefore,
(15−2)m(8−2)m
=(13×6)m
=78m
2
Therefore, the room area is 15×8 = 120m
2
The carpet area is 78m
2
The fraction of the area uncovered =
120
120−78
=
120
42
=
20
7
Step-by-step explanation: