A room is 18m long, 14m wide and 8m gh.find the total surface area of the six faces of the room?
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Answered by
10
sa=2(lb+lh+bh)
sa=2*(18*14+18*8+14*8)
sa=2*(252+144+112)
sa=2*(508)
sa=1016
sa=2*(18*14+18*8+14*8)
sa=2*(252+144+112)
sa=2*(508)
sa=1016
Answered by
14
Long=18m,wide=14m,high=8m
Total surface area =2(lb+bh+hl)
=2(18×14+14×8+8×18)m sq
=2(252+112+144)m sq
=2×508m sq
=1016m sq (ans)
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