Math, asked by duttatanisha941, 2 months ago

A room is 18m long 4m wide, It's floor is to be covered with rectangular tiles of size 9cm by 8cm. Find the cost of tiles at 5.25 per tile.​

Answers

Answered by Anonymous
41

ANSWER :-

  • Cost of tiles used is 525.

GIVEN :-

  • Floor of room has dimensions 18m × 4m.
  • Rectangular tiles has dimensions 9cm × 8cm.
  • Cost of one tile is 5.25.

TO FIND :-

  • The total cost of tiles.

TO KNOW :-

Area of rectangle = length × breadth

1m = 100cm

SOLUTION :-

Firstly we will convert the dimensions of room to cm as dimensions of tiles are given in cm.

As , 1m → 100cm

Dimensions of room becomes 1800cm × 400cm

Let 'n' numbers of tiles can be fit in the room .

So, Area of all tiles will be equal to Area of room

→ n × Area of one tile = Area of room

→ n × 9 × 8 = 1800 × 400

→ n × 72 = 7200

→ n = 7200/72

n = 100

Hence , 100 tiles are used to cover the floor of room.

___________________

1 tile costs 5.25.

100 tiles will cost → 5.25 × 100

Hence , Total cost of tiles that are used is 525.

___________________

THINGS TO REMEMBER :-

  • Make sure that all the values are in same units . In this question , dimensions of tiles were given in cm and that of room in m.

MORE TO KNOW :-

★ Area of square = side²

★ Area of triangle = (1/2) × bh

★ Area of circle = πr²

★ Area of semi-circle = πr²/2

★ Area of trapezium = h(sum of parallel sides/2)

★ Area of parallelogram = b × h

Answered by Anonymous
763

Question:-

A room is 18m long 4m wide, It's floor is to be covered with rectangular tiles of size 9cm by 8cm. Find the cost of tiles at 5.25 per tile.

Given:-

• Length of room = 18m

• Width of room = 4m

• Length of tile = 9cm

• Breadth of tile = 8cm

To find :-

Cost of tiles

Using Formula :-

Area of rectangle = l × b

Solution :-

Length of room = 18m = 1800cm

Breadth of room = 4m = 400cm

Area of room = l × b

= 1800 × 400

= 7200cm².

Area of room = 7200cm².

Length of tile = 9cm

Breadth of tile = 8cm

Area of tile = l × b

= 9 × 8

= 72cm²

Area of tile = 72cm²

No. of tiles = Area of room / Area of tile

= 7200cm²/72cm²

= 100

No. of tiles = 100

Cost of 1 tile = 5.25

Cost of 100 tiles = 5.25 × 100

= Rs.525

Therefore,

Cost of tiles = Rs.525

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