Question

A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm.Find the cost of covering the floor with tiles at the rate of 2 4.50 per tile ​

Answer 1

Answer:

12 tiles

Step-by-step explanation:

Area of the room = 4.5 x 4

=

$18 {m}^{2}$

= 1800 cm

Area of one tile = 15 x 10

=

$150 {m}^{2}$

No of tiles required =

$\frac{area \: of \: room}{area \: of \: one \: tile}$

= 1800 cm ÷ 150 cm

=12 tiles

Answer 2

Answer:

I hope it will help you.

Step-by-step explanation:

Area of the floor = length * breadth

= 4.5*4

=18 m^2

or. = 180000 cm^2

Area of 1 tile = length * breadth

=15 * 10

= 150 cm^2

Total tiles to be needed to cover the floor=

$\frac{180000}{150 } \\ = 1200 \\ \\ cost \: of \: 1 \: tile \: = rs. \: 24.50 \\ cost \: of \: 1200 \: tiles = 1200 \times 24.50 \\ = 29400$