Math, asked by adityasharmajan964, 1 year ago

A room is 4.5m long and 4m wide.the floor of the room iscto be covered with tiles of size 15cm by 10cm.find the cost of covering the floor with tiles at thecrate of RS.5.50 per tile?

Answers

Answered by EmmanuelThomas
25
total area of floor=18 sq.m
area of tile=150 sq.cm=1.5sq.m
no of tiles =18/1.5=12
total cost = 12*5.5=66 rupees
Answered by gadakhsanket
20

Dear Student,

◆ Answer -

Total cost = ₹ 6600

● Explaination -

No of tiles required is -

No of tiles = area of floor / area of each tile

No of tiles = (4.5 × 4) / (0.15 × 0.1)

No of tiles = 1200

Cost of covering floor is -

Total cost = 1200 × 5.50

Total cost = ₹ 6600

Hence, the cost of covering the floor with tiles is ₹ 6600.

Thanks dear. Hope this helps you...

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