Question

A room is 6 m long, 4 m broad and 3 m high. Find the cost of laying tiles on its floor and four walls at the cost of Rs. 80/m² .

Answer 1

Hi friend
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Your answer
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Length of a room = l = 6 m

Breadth of the room = b = 4 m

Height of the room = h = 3 m

Now,

Area to be laid with tiles = Area of base + area of four walls

= [ (6 × 4) + 2(6 + 4) × 3] m²

= [24 + 6 × 10] m²

= [24 + 60] m²

= 84 m²

Now,

Rate of laying tiles = Rs 80/m²

So, Cost of laying tiles = Rs (80 × 84) = Rs 6720

HOPE IT HELPS

Answer 2

Answer

Dimensions:

Length = 6 m

Breadth = 4 m

Height = 3 m

Area of four walls = 2h ( l + b )

= 2 × 3 ( 6 + 4 )

= 6 × 10

= 60 m^2

Area of floor = lb

= 6 × 4

= 24

Total area = 60 + 24

= 84 m^2

Cost = 80 × 84

= Rs 6720