Question

A room is 680. cm long and 320 cm wide. it is to be paved with square marble tiles of side 40 cm. how many such tiles will be required?



please tell me answer till 5 Feb and it should be with explanionation.​

Answer 1

Answer:

Length of hall is (4b-7) metres.

Step-by-step explanation:

According to the Question

It is given that,

length of a rectangular hall is 7 metres less than 4 times the breadth of the hall

Let the breadth be b m

According to the Given Statement

length of a rectangular hall is 7 metres less than 4 times the breadth of the hall.

Length of hall = 4× breadth of hall -7

↠ Length of hall = (4b - 7) metres

Hence, the length of the hall is (4b-7) metres.

Additional Information !!

\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered} \end{gathered}FormulasofAreas:−⋆Square=(side)2⋆Rectangle=Length×Breadth⋆Triangle=21×Breadth×Height⋆Scalene△=s(s−a)(s−b)(s−c)⋆Rhombus=21×d1×d2⋆Rhombus=21d4a2−d2⋆Parallelogram=Breadth×Height⋆Trapezium=21(a+b)×Height⋆EquilateralTriangle=43(side)2