A room is 6m by 8m. What is the length of the longest metallic rod that can be kept on the floor of the room? If the height of the room is 10m , what is the longest rod that can be kept in the room ?
Answers
Answered by
0
Answer:
Given that:
length l=12m
breadth b=9m
and
height h=8m
Longest rof that can be placed in a room is nothing but its diagonal.
Length of diagonal of a cuboid=
(l
2
+b
2
+h
2
)
Length of longest rod =
(12
2
+9
2
+8
2
)
m=
(144+81+64)
m=
289
m=17m
The length of the longest rod is 17m.
Answered by
0
Step-by-step explanation:
Given:-
- Length of room(l) = 6m
- Breadth of room(b) = 8m
- Height of room(h) = 10m
★Concept:-
- Since the room is a cuboid the longest object which can be kept in the room is equal to length of diagonal of room in fact longest object kept in any cuboid of any dimensions is equal to the length of its diagonal.
- So diagonal of cuboid = √l²+b²+h²
→Solⁿ
=> length of longest rod = length of Diagonal of room
=> length of rod = √6²+8²+10²
=> length of rod = √36+64+100
=> length of rod = √200 = 10√2
So, length of longest metallic rod which can be kept in the room is 10√2m.
Similar questions