Math, asked by Subhjotkaur, 1 year ago

A room is 6m long,5m broad and 4m high.there is a door 3m by 1m and two windows of size 1.5m by 1m.find the cost of plastering the walls at rs. 8 per m square.

Answers

Answered by Madhu123mri
9
Length of room- 6m= L
Breadth of room- 5m= B
Height of room- 4m= H

Dimensions of the door= 3m*1m

Therefore area of the door= 3m^2

Dimensions of the windows= 1.5m*1m

Area of the windows= 2(1.5*1) [as there are two windows]
=3m^2

Area of 4 walls= 2(l+b)*h

Area of 4 walls= Lateral surface area (L.S.A)= 2(6+5)*4

L.S.A= 2*11*4

L.S.A= 88m^2

Area of 4 walls to be plastered= (L.S.A)-(Area of door+Area of two windows)

=88-(3+3)

=82m^2

Rate of plastering= Rs. 8 per square metre

Rate of plastering walls= 82×8

= Rs. 656









Subhjotkaur: Thank you so much
Madhu123mri: You're welcome!
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