Math, asked by Anonymous, 3 months ago

A room is 7 m long, 4 m broad and 3.5 m high. It has two doors each 1.5 m by 2 m and two windows each 75 cm by 75 cm calculate.

(a) Area of Walls and roof.

(b) The cost of white washing the wall and roof at Rs. 8 per m^2.​

Answers

Answered by paridhi3350
1

A room is 7 m long, 4 m broad and 3.5 m high. It has two doors each 1.5 m by 2 m and two windows each 75 cm by 75 cm calculate.

(a) Area of Walls and roof.

(b) The cost of white washing the wall and roof at Rs. 8 per m^2.

Answered by SachinGupta01
9

Part (a)

 \sf \: (a)  \: Area \:  of \:  roof  \: =  \: Length  \: \times  \: Breadth

 \sf \:  =  \: 7m \:  \times  \: 4m \:  =  \: 28m^{2}

 \sf \: Area  \: of \:  4  \: walls \:   \: (Lateral \:  Surface  \: Area)  \: =  \: 2(L + B)h  \: sq.  \: unit

  \sf \:  =  \: 2(7 + 4) \times  3.5 \: m^{2}

  \sf \:  =  \: 2 \times 11\times  3.5 \: m^{2}

  \sf \:  =  \: 77 \: m ^{2}

Part (b)

 \sf \: Area  \: of \:  two \:  doors \:  =  \: 2 \:  \times  \:  \: (1.5m \times 2m)  \: = \:  2  \: \times \:  3.0 m ^{2}

 \sf \: = 6.0  \: m\: ^{2}

 \sf \: Area  \: of  \: two \:  windows \:  = \:  2  \: \times \:  (75 cm \:  \times  \: 75 cm)

 \sf \: = 2 \:  \times  \: (0.75 \times 0.75)

 \sf \: = 2 \:  \times  \: (0.75 \times 0.75)  \:  =  \: 1.125 \: m^{2}

 \sf \: Area  \: of  \: Wall  \: and \:  the  \: roof  \: to  \: be \:  white \:  washed \:  =

 \sf \:   [{(Area  \: of \:  4  \: walls)  \: +  \: (Area  \: of \:  roof)}]  \: - [{(Area  \: of \:  door) + (Area \:  of  \: windows)}]

 \sf \: = (77 \:  m^{2}  \:  +  \: 28 \: m ^{2} ) \:  -  \: (6.0 \: m ^{2}  + 1.125 \: m \: ^{2} )

 \sf \:  =  \: 105 \: m ^{2}  \:  -  \: 7.125 \: m ^{2}

 \sf \:  =  \: 97.875 \: m \:  ^{2}

 \sf \: Cost \:  of  \: White \:  washing  \: =  \: Rs. (97.875  \: \times  \: 8)

 \sf \: \:  Rs.  \: 97.875  \: \times  \: 8 \:  =  \:  Rs.  \: 783

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