Question

A room is 7m 35 cm broad and 11m 55cm long. The floor of the room is to be covered with square tiles .Find the length of the largest tile that can be used.

Answer 1

7.35m=735cm
11.55m=1155cm
HCF(735,1155)= side of the tile (largest possible)
=105

Answer 2

Answer:

The length of the largest tile that can be used is 105.

Step-by-step explanation:

Given : A room is 7m 35 cm broad and 11m 55cm long. The floor of the room is to be covered with square tiles.

To Find  : The length of the largest tile that can be used?

Solution :

Dimension of the room,

Length is 7 m 35 cm

1 m=100 cm

7 m=700 cm

So, Length is 735 cm

Breadth is 11 m 55 cm

1 m=100 cm

11 m=1100 cm

So, Breadth is 1155 cm

Area of the room is

$A=L\times B$

$A_r=735\times 1155$

Size of largest square tile is

H.C.F of 735 and 1155

$735=3\times 5\times 7\times 7$

$1155=3\times 5\times 7\times 11$

$HCF(735,1155)=3\times 5\times 7$

$HCF(735,1155)=105$

Area of 1 tile is

$A_t=105\times 105$

Number of tiles required is

$n=\frac{A_r}{A_t}$

$n=\frac{735\times 1155}{105\times 105}$

$n=77$

The length of the largest tile that can be used is 105.