Question

A room is 7m long and 5m broad. It has one door measuring (2m by 1.5m) and two windows, each measuring (1.5 m by 1m). The cost of painting the walls of the roon at ₹80 per metre is ₹5280. Find the height of the room.




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Answer 1

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Answer 2

Answer:

Height of the room is 3m

Step-by-step explanation:

Question:-

A room is 7m long and 5m broad. It has one door measuring (2m by 1.5m) and two windows, each measuring (1.5 m by 1m). The cost of painting the walls of the roon at ₹80 per metre is ₹5280. Find the height of the room.

Given:-

The room is 7m long and 5m broad

Length of door=2m

Breadth of door=1.5m

Length of one door=1.5m

Breadth of one door=1m

The cost of painting the walls of the roon at ₹80 per metre is ₹5280

To find:-no

The height of the room

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$\huge\mathcal\pink{Solution:-}$

First we have to find the area of two windows

According to the question it is given that,

Length of one window=1.5m

Breadth of one window=1m

So the window is in rectangular shape

Area of window=length×breadth

On substituting the values we get,

=1.5m×1m

$= 1.5 {m}^{2}$

So area of two doors=

$1.5 {m}^{2} \times 2$

$= 3 {m}^{2}$

Next we have to find area of door

Length of door=2m

Breadth of door=1.5m

So the door is in rectangular in shape

Area of door=length×breadth

On substituting the values we get,

=2m×1.5m

$= 3 {m}^{2}$

Area of the walls to be painted= Area of 4 faces of the room - Area of the door- Area of 2 windows

$7 \times h + 7 \times h + 5 \times h + 5 \times h -3m - 3m$

$\mapsto \: 24h - 6$

Area of wall painted

$= \frac{total \: cost \: of \: painting \: the \: wall}{cost \: of \: painting \: 1 \: sq.m \: of \: the \: wall}$

On substituting the values we get,

$= \frac{5280}{80} = 66 \: sq.m$

Thus, 24h-6=66

24h=66+6

24h=72

$h = \frac{72}{24}$

$h = 3m$

Therefore the height of the room is 3m