Question

A room is 8.5 m long, 6.5m broad and 3.4 m high. It has two doors, each measuring 1.5m by 1m and two windows each measuring 2m by 1m. What is the cost of painting the walls at Rs. 160 per m²​

Answer 1

Step-by-step explanation:

Dimensions of room=

$8.5 \times 6.5 \times 3.4$

Area of four wall=

$2(l + b) \times h$

=

$2(8.5 + 6.5) \times 3.4 = 102m {}^{2}$Area of two doors

$2 \times 1.5 \times 1 = 3m {}^{2}$

Area of two windows=

$2 \times 2 \times 1 = 4m {}^{2}$

Area to be painted=

$(102 - 3 - 4) m { }^{2} = 95m {}^{2}$

.°. Cost of painting the walls=

$95 \times 160 = rs15200$

Answer 2

Answer:

Rs 28936

Step-by-step explanation:

product of long , broad,high =187.85 -area of doors and windows= 180.85

180.85 ×160=28936