Question

A room is 8.60m long and 6.25 m wide. Its floor is to be covered with the designer tiles of size 20 cm x 10 cm. Find the cost of the tiles if one tile is Rs. 100

Answer 1

Answer:

area of room= lxb

6.25x8.60=53.75 sq. m

area of tile-lxb

20cmx10cm=200 sq. cm

no. of tile = area of tile ➗ area of room

= 53.75=5375.00cm➗200cm=

26 tiles

no. of tiles.x cost of 1 tile =26x100=2600 is the cost of tiling

Step-by-step explanation:

first find the area of room.

find the area of tile

to find the no. of times we will divide the area of tile with area of room.

to find the cost of tiling multiply the no. of tile with cost of 1 tile

Answer 2

Step-by-step explanation:

lenght if room = 860 cm

breadth of room = 625 cm

area = 860×625

length of tile= 20

bradth of tile =10

area 20×10

no of tiles reqiured =

860×625

20×10= 2687.50

cost of one tile = 100 rupees

cost of 2687.50 tiles =2687.50×100

= 268750 rupees