Question

A room is 9.68 long and 6.2m wide. It's floor to be covered with tiles of size 22cm by 10cm .Find the total cost of the tiles at the rate of Rs.25 per tiles​

Answer 1

HOPE IT HELPS :

Given :

Dimensions of room are :

Length = 9.68 m

Breadth = 6.2 m

Dimensions of a single tile :

Length = 22 cm = 0.22 m

Breadth = 10 cm = 0.1 m

Solution :

Area of room = ( 9.68 x 6.2 ) $m^{2}$

Area of a single Tile = ( 0.22 x 0.1 ) $m^{2}$

Hence number of tiles required are :

Tiles = Area of floor / Area of Tile

Tiles = 2728

Hence amount required = (2728) x (Cost of one tile)

Amount = 68200 Rs.

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Answer 2

Answer:

68200 is correct please thanks me