Question

a room is 9.68m long and 6.2m wide. its floor is to be covered with rectangular tiles of size 22cm by 10cm. find the total cost of the tiles at the rate of 3 per tiles.

Answer 1

Answer:

Step-by-step explanation:

Given length of room = 9.68 metres

Given breadth of room = 6.2 metres

So area = lxb = 9.68x6.2 = 60.016

Area of tile = 0.22x0.1(in metres) = 0.022

no of tiles required = 60.016/0.022 = 2728

cost per each tile = 3

therefore total cost = 2728x3 = 8184 rupees

Answer 2

$hey \: mate \: heres \: ur \: answer$
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$answer \: \\ \\ Rs14875$

$step \: by \: step \: explaination$

$Lenght \: of \: the \:room = 9.68m$

$Breadth \: of \: the \: room = 6.2m$

$Length \: of \: the \: room = 9.68 \times 1000 = 9680cm$

$Breadth \: of \: the \: room \: = 6.2 \times 100 = 620cm$

$Area \: of \: the \: room = l \times b \\ (where \: l = length = 9680 \: and \\ b = breadth = 620cm)$

$area \: of \: room = 9680cm \times 620cm = 6,001,600 {cm}^{2}$

$Area \: of \: one \: tile = 22cm \times 10cm = 220cm^{2}$

$Number \: of \: tiles \: required = \frac{area \: of \: room}{area \: of \: tile}$

$number \: of \: tiles \: required= \frac{6001600}{220}$

$number \: of \: tiles \: required =27,280$

$Cost \: of \: tiling \: at \: the \: rate \: of \: Rs \: 3 \: per \: tile$

$cost \: of \: tiling = (number \: of \: tiles) \times (cost \: of \: 1 tile)$

$cost \: of \: tiling \: = 27280 \times 3$

$cost \: of \: tiling \: the \: room \: at \: the \: rate \: of \: Rs3 \: per \: tile =Rs81,840$

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Hope this helps you!!! ^_^
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