Question

A room is 9 m by 8 m by 6.5 m. It has one door of dimensions (2 m x 1.5 m) and four
windows each of dimensions (1.5 mx1 m). Find the cost of painting the walls at 50 per m.
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Answer 1

Answer:

Given dimension of room =9m×8m×6.5m

now CSA of room =2(lh+bh)

=2h[l+b]

CSA of room =2×6.5[9+8]=13×17

CSA of room =221m

2

....(1)

now

area of door =2×1.5=3m

2

area of 4 window =4x(1.5,1)=6 m^{2}$$

area to be painted =CSA of room -(arof door)-(ar of window)

area to be painted =221−6−3=212m

2

cost of painting = area x 50 =212×50Rs

cost of painting =10,600 Rs