A room is 9m long, 8m broad and 6.5 m high. It has one door of dimensions 2m × 1.5m and 3 windows each of dimensions 1.5 m × 1m. Find the cost of whitewashing the walls at RS. 3.80 per square metre. (Pls explain with step by step explaination. I don't want direct answers).
Answers
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Answer:
Given Length of a room = 9 m
Breadth of a room = 8 m
Height of a room = 6.5 m
Area of 4 walls ( becaus ea room has 4 walls) = 2(l + b) h = 2 (9 m + 8 m) x 6.5 m = 2 x 17 m x 6.5 m = 221 m ^2
Length of a door = 2 m
Breadth of a door = 1.5 m
Area of a door = Length x Breadth = 2 m x 1.5 m = 3 m2
Length of a window = 1.5 m
Breadth of a window = 1 m
Since, area of one window = Length x Breadth = 1.5 m x 1 m = 1.5 m2
Thus, Area of 3 such windows = 3 x 1.5 m2 = 4.5 m2
Area to be white washed = Area of 4 walls – (Area of one door + Area of 3 windows)
Area to be white washed = [221 – (3 + 4.5)] m2 = (221 – 7.5) m2 = 213.5 m^2
We have cost of white washing for 1 m2 area = Rs. 3.80
Cost of white washing for 213.5 m2 area = Rs. (213.5 x 3.80) = Rs. 811.30
HOPEFULLY YOU UNDERSTOOD