A room is in the from of a cuboid of measures 6m× 4m × 3m× . How many cuboid boxes can be stored in it ,if the volume of one box is 0.8m3?
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Answered by
2
According to the situation
Volume of the room = (no. of boxes)x(volume of one small box)
On solving we get no. of boxes = 90
Volume of the room = (no. of boxes)x(volume of one small box)
On solving we get no. of boxes = 90
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Answered by
0
Given dimensions of the cuboid = 6m,4m,3m
So
![volume = 6 \times 4 \times 3 volume = 6 \times 4 \times 3](https://tex.z-dn.net/?f=volume+%3D+6+%5Ctimes+4+%5Ctimes+3)
![volume = 72 \: {m}^{3} volume = 72 \: {m}^{3}](https://tex.z-dn.net/?f=volume+%3D+72+%5C%3A++%7Bm%7D%5E%7B3%7D+)
Given volume of small cuboids =O.8 mcube
Let the number of cuboids be n
n×0.8=72 [volume must be equal]
![n = \frac{72}{0.8} \\ \\ \\ n = 90 n = \frac{72}{0.8} \\ \\ \\ n = 90](https://tex.z-dn.net/?f=n+%3D++%5Cfrac%7B72%7D%7B0.8%7D++%5C%5C++%5C%5C++%5C%5C+n+%3D+90)
Thus 90 cuboids
So
Given volume of small cuboids =O.8 mcube
Let the number of cuboids be n
n×0.8=72 [volume must be equal]
Thus 90 cuboids
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