A room is of 11m × 8m × 5m . Find the cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc.
1 point
1390 Rs.
112 Rs.
1112 Rs.
278 Rs.
Answers
Heya !
Given:-
- Dimensions of the room = 11×8×5 cm.
- Cost /m = 5Rs.
To find :-
- Cost of cementing the 4 walls and the floor.
- so for that we need to find C.S.A + area of floor.
Formulas to be used.
- C.S.A = 2h(l+b)
- Area of floor = l×b
Solution
Area to be cemented = C.S.A + area of floor
=> 2h(l+b) + l×b
=> 2(5)[11+8] + 8×11
=> 10(19) + 88
=> 190 + 88
=> 278 m²
Hence, the cost = 278×5 = 1390Rs.
Therefore, option A is Right...
_____________________________
answer:-
1390 RS
EXPLANATION:-
Given:
Length of room, l = 11 m
Breadth of room, b = 8 m
Height of room, h = 5 m
To find:
The cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc?
Solution:
Area of Rectangular floor:
⇒ Length × Breadth
⇒ 11 × 8
⇒ 88 m
Area of four walls = Curved surface area of room
CSA of cuboidal room = 2(l + b)h
⇒ 2(11 + 8) × 5
⇒ 2 × 18 × 5
⇒ 190 m²
Area of four walls and floor of room:
⇒ 190 + 88
⇒ 278 m²
Cost of cementing its four walls and floor at the rate of ₹5 per square metre,
⇒ 278 × 5 = 1390 Rs.
∴ Hence, Cost of cementing its four walls and floor is 1390 Rs.
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