Math, asked by janvibalhara9, 5 months ago

A room is of 11m × 8m × 5m . Find the cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc.
1 point
1390 Rs.
112 Rs.
1112 Rs.
278 Rs.​

Answers

Answered by Anonymous
1

Heya !

Given:-

  • Dimensions of the room = 11×8×5 cm.
  • Cost /m = 5Rs.

To find :-

  • Cost of cementing the 4 walls and the floor.
  • so for that we need to find C.S.A + area of floor.

Formulas to be used.

  • C.S.A = 2h(l+b)
  • Area of floor = l×b

Solution

Area to be cemented = C.S.A + area of floor

=> 2h(l+b) + l×b

=> 2(5)[11+8] + 8×11

=> 10(19) + 88

=> 190 + 88

=> 278 m²

Hence, the cost = 278×5 = 1390Rs.

Therefore, option A is Right...

_____________________________

Answered by jojopojo540
0

answer:-

1390 RS

EXPLANATION:-

Given:

Length of room, l = 11 m

Breadth of room, b = 8 m

Height of room, h = 5 m

To find:

The cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc?

Solution:

Area of Rectangular floor:

⇒ Length × Breadth

⇒ 11 × 8

⇒ 88 m

Area of four walls = Curved surface area of room

CSA of cuboidal room = 2(l + b)h

⇒ 2(11 + 8) × 5

⇒ 2 × 18 × 5

⇒ 190 m²

Area of four walls and floor of room:

⇒ 190 + 88

⇒ 278 m²

Cost of cementing its four walls and floor at the rate of ₹5 per square metre,

⇒ 278 × 5 = 1390 Rs.

∴ Hence, Cost of cementing its four walls and floor is 1390 Rs.

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