Question

A room is of 11m × 8m × 5m . Find the cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc.
1 point
1390 Rs.
112 Rs.
1112 Rs.
278 Rs.​

Answer 1

Given:

• Length of room, l = 11 m
• Breadth of room, b = 8 m
• Height of room, h = 5 m

To find:

• The cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc?

Solution:

Area of Rectangular floor:

⇒ Length × Breadth

⇒ 11 × 8

⇒ 88 m

Area of four walls = Curved surface area of room

• CSA of cuboidal room = 2(l + b)h

⇒ 2(11 + 8) × 5

⇒ 2 × 18 × 5

⇒ 190 m²

Area of four walls and floor of room:

⇒ 190 + 88

⇒ 278 m²

Cost of cementing its four walls and floor at the rate of ₹5 per square metre,

⇒ 278 × 5 = 1390 Rs.

∴ Hence, Cost of cementing its four walls and floor is 1390 Rs.

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

A room is of 11 m × 8 m × 5 m . Find the cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc.

• 1390 Rs.
• 112 Rs.
• 1112 Rs.
• 278 Rs.

$\huge{\boxed{\rm{\red{Answer}}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Length of the room = 11 metres

• Breadth of the room = 8 metres

• Height of the room = 5 metres

• Rupees 5 per m² is the rate of cementing of 4 walls and floors including the windows and the doors.

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• The cost of cementing its four walls and floors at the rate of Rupees 5 per metre² including the windows and doors.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• The cost of cementing its four walls and floors at the rate of Rupees 5 per metre² including the windows and doors = 1390 Rupees

$\large{\boxed{\boxed{\sf{We \: also \: write \: this \: as}}}}$

• Length as L

• Breadth as B

• Height as H

• Area as A

• Metres as m.

• Rupees as Rs.

• Curved Surface Area as CSA

$\large{\boxed{\boxed{\sf{What \: does \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: question \: 1st}}}}$

• In this question there is a room given of dimensions ( Length , Breadth , Height ). The dimensions are 11 m , 8 m , 5 m. Now the question says that we have to find the cost of cementing its four walls and floors at the rate of Rupees 5 per metre² including the windows and doors.

$\large{\boxed{\boxed{\sf{How \: to \: solve \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's \: see \: the \: given \: procedure}}}}$

• Firstly we have to use the formula of area of Rectangle after that putting the values we get area of Rectangle. Then,Using the formula to find area if 4 walls after that using the formula to find CSA of the room after that putting the values we get a number then we have too add it with arex of Rectangle that is already find by us. After the the answer is cinetgen we have to multiply the answer with 5 and we get our final result that is 1390 rupees.

$\large{\boxed{\boxed{\sf{Let's \: do \: it \: properly}}}}$

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

$\bold{\green{\fbox{\green{To solve this question we have to use given formula}}}}$

$\bold{\green{\fbox{\green{Given formula is of area of rectangle}}}}$

$\large\underbrace\mathfrak\blue{A \: of \: rectangle \: formula}$

$\leadsto$ $\huge{\boxed{\underline{\sf{L × B}}}}$

$\large\orange{\texttt{Now}}$

$\large\orange{\texttt{According to the question}}$

$\small\red{\texttt{Area of rectangular floor}}$

➝ As we know that formula to find area of rectangle is Length × Breadth

$\large\orange{\texttt{So, let's carry on}}$

$\mapsto$ A = L × B

$\mapsto$ A = ( 11 × 8 ) m²

$\mapsto$ A = 88 m²

$\bold{\green{\fbox{\green{Now, we have to use given formula}}}}$

$\bold{\green{\fbox{\green{Given formula is to find a of 4 walls}}}}$

Area of four walls ↓

$\mapstosto$ $\huge{\boxed{\underline{\sf{CSA \: of \: room}}}}$

$\large\orange{\texttt{Now,}}$

$\large\orange{\texttt{According to the question}}$

$\small\red{\texttt{Area of four walls}}$

➝ As we know that the formula to find area of 4 room is CSA of room .

$\bold{\green{\fbox{\green{Now, we have to use given formula again}}}}$

$\bold{\green{\fbox{\green{Given formula is to find CSA of room}}}}$

$\large\underbrace\mathfrak\blue{CSA \: of \: room}$

$\leadsto$ $\huge{\boxed{\underline{\sf{2[l+b]h}}}}$

$\large\orange{\texttt{Now,}}$

$\large\orange{\texttt{According to the question}}$

$\small\red{\texttt{CSA of the room}}$

➝ As we know that the formula to find CSAl of room is 2(l+b)h

$\large\orange{\texttt{So, let's carry on}}$

$\mapsto$ 2(11+8) × 5

$\mapsto$ 2 × 19 × 5

$\mapsto$ 10 × 19

$\mapsto$ 190 m²

☃ Area of 4 wall and floor of room

$\mapsto$ 190 + 88

$\mapsto$ 278 m²

The cost of cementing its four walls and floors at the rate of Rupees 5 per metre² including the windows and doors,

$\mapsto$ 278 × 5

$\mapsto$ 1390 Rupees.

The cost of cementing its four walls and floors at the rate of Rupees 5 per metre² including the windows and doors, Rupees 1390.

Hope it's helpful

Thank you :)