Math, asked by janvibalhara9, 6 months ago

A room is of 11m × 8m × 5m . Find the cost of cementing its four walls and floor at the rate of ₹5 per square metre including doors and windows etc.
1 point
1390 Rs.
112 Rs.
1112 Rs.
278 Rs.​

Answers

Answered by syedqasid408
1

Step-by-step explanation:

Given that l =11m =8mh = 5 m top of the room = l×b = 11× 8 = 88 ...... a room is of 11m×8m×5m....... at the rate of Rs 5 per square including door and window . 278m floor at the rate of Rs 5=278×5= 13900 rupees

Answered by Anonymous
1

Heya !

Given:-

Dimensions of the room = 11×8×5 cm.

Cost /m = 5Rs.

To find :-

Cost of cementing the 4 walls and the floor.

so for that we need to find C.S.A + area of floor.

Formulas to be used.

C.S.A = 2h(l+b)

Area of floor = l×b

Solution

Area to be cemented = C.S.A + area of floor

=> 2h(l+b) + l×b

=> 2(5)[11+8] + 8×11

=> 10(19) + 88

=> 190 + 88

=> 278 m²

Hence, the cost = 278×5 = 1390Rs.

Therefore, option A is Right...

_____________________________

Similar questions
English, 6 months ago